0 votes
in SoSci Survey (English) by s145019 (110 points)

Hello,

I would like to link a word with a text block in my survey.
You told me last week that I should use the placeholder% info-link%.
But I always get the warning "The first parameter specified for replace () is not a valid placeholder:% info-link%".
How can I fix the problem.
Kind regards,

1 Answer

0 votes
by SoSci Survey (312k points)

The first parameter specified for replace () is not a valid placeholder:% info-link%".

Please make sure that the first percentage sign is not followed by a space:

replace('%info-link%', ...)

If that does not help, please add your current PHP code to the question. Please use the button {} for format the code as code. Thank you.

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